Question

The middle term in the expression of (2m-3n)^2 is _______.​

Answer 1

Answer:

(2m-3n)^2

use identity (a-b) = a^2 -2ab +b^2

= (2m)^2 - 2(2m)(3n) + (3n)^2

= 4m^2 - 2(6mn) + 9n^2

= 4m^2 - 12mn +9n^2

if u want the middle term it is -12mn

u can also split the same for factorisation