The middle term of an ap is 52. Find the sum of its first and last term
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Given a
10
=52
a
n
=a+(n−1)d
52=a+9d(1)
also, a
17
=20+a
13
a+16d=20+a+12d
4d=20
d=5(2)
From (1) and (2)
52=a+9×5
a=7
The AP is: 7,12,17,22,...
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