The middle term of the progression 4,9,14.....104 is
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Answer: the middle most term of the series is the 11th term = 54
Step-by-step explanation:
The AP is 4, 9, 14,....., 104
a(first term)= 4, d(common difference)= 9-4= 5, l(final term)= 104
n(total number of terms= ?
using the formula: l= a + (n-1)*d we can find the total number of terms in the AP
Substitute the values in the formula
We get n= 21
Middlemost term of the series is= [(21 + 1) / 2]th term= 11th term
Using the formula l = a + (n-1)*d, we find the 11th term
11th term = a + (11-1)*d = 4 + 10*5 = 4 + 50 = 54
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