Question

The midpoint of (0,2) and
(4,2) is

Answer 1

$formula \: for \: midpoint \\ = \frac{( log_{x}(1) + log_{x}(2) }{2} \: and \: \frac{( log_{y}(1) + log_{y}(2) }{2} \\ = \frac{(0 +4) }{2} \: and \: \frac{(2 + 2)}{2} \\ \frac{4}{2} \: and \: \frac{4}{2} \\ 2 \: and \: 2 \\ hence \: the \: mid \: point \: is \: (2 \: comma \: 2)$

Answer 2

Answer:

(2,2) is the mid point..

Step-by-step explanation:

we know the midpoint formulae:

(x1 + x2) / 2 , (y1 + y2) / 2

x1 = 0 ; x2 = 4

x1 = 0 ; x2 = 4y1 = 2 ; y2 = 2

Then,

=(0 + 2)/2 , (2 + 2)/2

= 4/2 , 4/2

= (2,2)

The mid point between (0,2) and (4,2) is (2,2)....

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