Question

the midpoint of(3p,4) and (-2,2q)is(2,6) then the value of p is ?​

Answer 1

Answer:

Here's your answer....

(2,6)=

$\frac{(3p - 2)}{2} \: \: \frac{(4 +2q) }{2} \\ \\ 3p - 2 = 4 \\ 4 + 2q = 12 \\ p = 2 \: and \: q = 4 \\ \therefore \: p + q = 4 + 2 \\ = 6 \\ hence \: value \: is \: 6$

$\Large\textsf{Hope \: It \: Helped}$

Answer 2

Step-by-step explanation:

let 3p+(-2)/2=2

3p-2=4 ( multiply by 2)

3p=6 (added by 2)

p=2