Question

the midpoint of line segment joining the points (3,m) and (5,1) lies on the line x+y=5. Find the value of m.​

Answer 1

Answer:

A(3,4) and B(k,6). P(x,y) is the mid point of AB. So

(x,y) = ( (3+k)/2 , (4+6)/2 )

=> x = (3+k)/2. ….(1) and y =5.

Substituting y=5 in the equation x+y-10=0

We get x+5–10 = 0 => x = 5.

Substituting X=5 in (1) we get

5 = (3+k)/2 => 3+k = 10 => k = 7

Step-by-step explanation:

x= (3+k)/2

y= (4+6)/2 = 5

(3+k)/2 + 5 - 10 = 0

(3+k) + 10- 20= 0

k = 7