Question

The midpoint of the class is 15 and the class size is 10, then the lower limit of the class is​

Answer 1

Answer:

10

Step-by-step explanation:

Midpoint of the class=15

class size =10

lower limit =x

higher limit =x+10

midpoint = $\frac{x+x+10}{2} =15$

               =>$\frac {2x+10}{2}=15$

               =>$x+5=15$  

               =>$x=15-5=10$