Question

The midpoint of the line segment from P1 to P2 is (-1, 4). If P1 = (-3, 6), what is P2?

Answer 1

Let coordinates of the mid point be x, y

Flat coordinates of P1 be X1, Y1 and P2 be X2, Y2

Buy midpoint theorem,

X = ( X 1 + X 2) / 2 and y = (Y1 + Y2 )/ 2

Substituting the values of X X 1 and y y1 we get

- 1 = - 3 + X 2 / 2 and 4 = 6 + Y 2 / 2

Multiplying throughout by 2

X2 - 3 = - 2 and Y2 + 6 = 8

Therefore X2 = 1 and Y2 = 2

And therefore the coordinates of P2 are 1, 2

Answer 2

Answer:

P2 is (1,2)

Step-by-step explanation:

P1 = (-3[x1],6[y1])                   P2 = (x2,y2)                midpoint P(x,y) = P(-1,4)

Midpoint formula, P(x,y) = { (x1 + x2)/2 , (y1 + y2)/2}

P(-1,4) = { ( -3  + x2)/2 , (  6 + y2)/2 }

p(x) = (-3 + x2)/2 = -1

      = -3 + x2 = -2

      = x2 = -2 + 3

      therefore, x2 = 1

p(y) = (6 + y2)/2 = 4

      = 6 + y2 = 8

      = y2 = 8 - 6

      therefore, y2 = 2

ans: P2 = ( x2, y2)

       P2 = (1, 2)