Question

The midpoint of the line segment joining points (-1,-12) and (-1,4) is
With explanation ...

Answer 1

Answer:

Given Question :-

The midpoint of the line segment joining points (-1,-12) and (-1,4) is

Answer

Given :-

The line segment joining points A(-1,-12) and B(-1,4)

To Find :-

Midpoint of AB.

Formula used :-

Midpoint Formula:-

⟼ Let us consider a line segment joining the points

$\pink{\sf \: A(x_1,y_1) \: and \: B(x_2,y_2)}$

⟼ Let C(x, y) be the midpoint of AB, then coordinates of midpoint C is given by

$\purple{\bf \:( x, y) = (\dfrac{x_1+x_2}{2} , \dfrac{y_1+y_2}{2} )}$

$\begin{gathered}\Large{\bold{\pink{\underline{CaLcUlAtIoN\::}}}} \end{gathered}$

⟼ Let C(x, y) be the midpoint of the line segment joining the points A(-1,-12) and B(-1,4).

⟼ Then, Coordinates of C is given by

$\sf \:( x, y) = (\dfrac{x_1+x_2}{2} , \dfrac{y_1+y_2}{2} )$

where,

$\bf \:x_1 = - 1 ,y_1 = - 12,x_2= - 1 ,y_2=4x$

⟼ So, we get

$\bf ( x, y) = (\dfrac{ - 1 - 1}{2} , \dfrac{ - 12 + 4}{2} )x,y)$

$\bf ( x, y) = ( - 1 , - 4)(x,y)$

⟼ Hence, the midpoint of the line segment joining points (-1,-12) and (-1,4) is (- 1, - 4)

Answer 2

Such types of question can be solved using the midpoint formula:-

(xm ,ym)=

$\frac{x1 + x2}{2} \: and \: \frac{y1 + y2}{2}$

-1 + (-1) ÷ 2 , -12 + 4 ÷2

= ( -1, -4)

Hence, the coordinates are (-1 and -4).

And it will lie in the third quadrant.