Question

The mighty troll climbs a 25km high mountain with an elephant in one hands and a cat in the other. It drops the elephant and a cat at the same time from his hand, calculate the time taken and speed by both to reach the ground? (t=70.71s, v=707.1m/s-1

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Answer 1

Answer:

The time taken and velocity achieved will be the same for both cat and elephant.

$v^{2}$ = 2gh = 2 X 10 X 25000 = 500000

or, v = $\sqrt{500000}$ = 707.1m/s

Also,

H = $\frac{1}{2} gt^{2}$

or, $t^{2}$ = $\frac{2H}{g}$ = $\frac{2 X 25000}{10}$ = 5000

or, t = $\sqrt{5000}$ = 70.71s

Answer 2

Given :

$v^{2}=2 \mathrm{gh}=2 \times 10 \times 25000=500000$$\text { or, } v=\sqrt{500000}=707.1 \mathrm{~m} / \mathrm{s}$

$\text { Also, }$

$\mathrm{H}=\frac{1}{2} g t^{2}$

$\text { or, } t^{2}=\frac{2 H}{g}=\frac{2 X 25000}{10}=5000$

$\text { or, } t=\sqrt{5000}=70.71 \mathrm{~s}$

The time taken and velocity achieved will be the same for both cat and elephant.