the milkman has to deliver milk to six houses. house a,b and c on the left house x,y and z on the right.the houses are linked to eachother along the path.
Answers
Step-by-step explanation:
Suppose, in the beginning there was x gallons of spring water in can No 1 and y gallons of milk in can No. 2 then,
can No. 1 can No. 2
In the Beginning x gallons of water y gallons of milk
After doubling contents of Can 2 x-y
water = x-y,
milk = 0 2y
water = y,
milk = y
After doubling contents of Can 1 2(x-y)
water = 2(3/4)(x-y),
milk = 2(1/4)(x-y) 2y-(x-y) i.e. (3y-x)
water = (1/2)(3y-x),
milk = (1/2)(3y-x)
After doubling contents of Can 2 2(x-y)-(3y-x) i.e. (3x-5y)
water = (3/4)(3x-5y),
milk = (1/4)(3x-5y) 2(3y-x)
water = (5/4)(3y-x),
milk = (3/4)(3y-x)
Now, we know that the number of gallons of Milk in Can 1 = number of gallons of Milk in Can 2
Hence: (1/4)(3x-5y) = (3/4)(3y-x)
Multiply by 4: 3x-5y = 3(3y-x)
Move x to one side and y to other: 6x = 14y
And so: x = (14/6)y
We ALSO know that the number of gallons of Water in Can 2 = number of gallons of Milk in Can 2 PLUS 1
Hence (5/4)(3y-x) = (3/4)(3y-x) +1
Multiply by 4: 5(3y-x) = 3(3y-x) + 4
Simplify: 2(3y-x) = 4
Replace "x" with "(14/6)y": 2(3y-(14/6)y) = 4
Simplify: (4/3)y = 4
Hence: y = 3
Now we know y=3, we also know that x = (14/6)y = 7
Hence, there was initially 7 gallons of water in can No. 1 and 3 gallons of milk in can No 2.
After all the mixings there would be 4½ gallons of water and 1½ gallons of milk in can No. 1 and 2½ gallons of water and 1½ gallons of milk in can No 2.
Hence, there is 3 more gallons of water than milk in can No 1.
Answer:
h the link to the hemlock symbolise the class will be in a bus to write you