Math, asked by keerthana612, 2 months ago

the min value of 16-8sin^2 theta +8 cos^4 theta/sin^2 2theta

a. √6
b.2√6
c.3√6
d.4√6

Answers

Answered by Anonymous

1

we have given that. f(x)=2sinxcosx−8sinx−− −−(1). For maximum and minimum value. f′( x)=0. ⇒2sinxcosx−8sinx=0..l

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