the min. value of n such that 1+3+3^2+3^3+......+3^n >1000 ...answer plz
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we know that
sum of n terms in gp = a (r^n-1)/(r-1)
so, (1) (3^n-1)/2 is greater than thousand.
now solve and n would come out to be 7.
If you want the solution as well, do tell me. I will try to solve it as soon as possible.
if you have any other doubts, don't hesitate to ask.
regards
nimit sharma
sum of n terms in gp = a (r^n-1)/(r-1)
so, (1) (3^n-1)/2 is greater than thousand.
now solve and n would come out to be 7.
If you want the solution as well, do tell me. I will try to solve it as soon as possible.
if you have any other doubts, don't hesitate to ask.
regards
nimit sharma
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