Math, asked by naveensaipuri, 7 months ago

THE MINIIMUM VALUE OF X²-8X+17

Answers

Answered by padmamaloth1986

2

Answer:

Step-by-step explanation:

Let y =x2−8x+17

=(x−4)2−16+17

=(x−4)2+1

⇒y≥1 for all real values of x as

(x−4)2≥0

Hence, minimum value of y is

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