Question

The minimum acceleration that must be imparted to the cart in the given figure. So that the block A will not fall (given p = 0.5 is the coefficient of friction between the surfaces of block and cart) is given by (1) 2 m/s2 (2) 20 m/s2 (3) 5 m/s2 (4) 7.5 m/s2​

Answer 1

Answer:

Due to frictional force, the block will be prevented from falling.

From figure, we have

N=ma 0 ....(i)

f=mg=μN....(ii)

Solving Eqs. (i) and (ii), we get

mg=μ(ma 0)⇒a 0 =g/μ.

Answer 2

The free-body diagram is given below.

For the block must not fall down, the net force in the vertical direction should be zero.

$\therefore f=mg$...(1)

Also, the block must move with the cart. As shown in the FBD, the only force in the direction of acceleration is normal.

$\therefore N=ma$...(2)

We also know, for friction,

$\mu N=mg$...(3)

From (2)

$\mu ma=mg\\\therefore a=\frac{g}{\mu}$

Given, $\mu = 0.5$

$\therefore a=\frac{5}{0.5} = 10 \ ms^{-2}$

To learn more about solving questions of friction, click on the links below:

https://brainly.in/question/8869901?msp_srt_exp=5

https://brainly.in/question/42591504?msp_srt_exp=5

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