The minimum acceleration with which a person can slide down a rope whose breaking strength is 60percent of his weight
Answers
Answered by
20
Answer: 2g/5
Explanation:
T = mg - ma
T= breaking force= 60×mg/100
m(g-a) = 60×mg /100
a= 10g - 6g /10
a=4g/10
a= 2g/5
Answered by
2
Answer:
The minimum acceleration is .
Explanation:
Given that :
Inertia force minimum
Force due to gravity
Dividing throughout with :
D'Alembert's concept is used in this procedure.
- We can solve this utilising dynamic equilibrium if we add the inertia force to the rope. Because he is accelerating downward, the inertia force acts upward (opposite to direction of acceleration). The human is still under the influence of tension and gravity.
- If , the rope tension is equal to the person's weight.
- NOTE: If he accelerates up the rope, the inertia force acts downward, causing the rope tension to exceed the person's weight.
Similar questions