Question

The minimum amount of O2(g) consumed per gram of reactant is for the reaction :

(Given atomic mass : Fe = 56,0 = 16, Mg = 24, P = 31, C = 12, H= 1)

(a) C3H2(g) +502(g)-3C02(g) + 4H2O(1) (b) PA(s)+502(g) →P,000(s)
(c) 4Fe(s) + 302(g) →2Fe2O3(s)
(d) 2Mg(s)+ O2(g) → 2MgO(s) T:​

Answer 1

option ( c ) ) 4Fe(s) + 302(g) →2Fe2O3(s)

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