The minimum and maximum distance of a satellite from the earth are 2r and 4r respectively.where r is the radius of the earth and m is the mass the earth. its maximum speed is
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(a) Applying conservation of angular momentum
mυ1(2R)=mυ2(4R)
υ1=2υ2 ..(i)
From conservation of energy
12mυ21−GMm2R=12mυ22−GMm4R ..(ii)
Solving Eqs. (i) and (ii), we get
υ2=GM6R−−−−√,υ1=2Gm3R−−−−−√
(b) If r is the radius of curvature at point A
mυ21r=GMm(2R)2
r=4υ21R2GM=8R3 (putting value of υ1)
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