Question

the minimum and maximum value of |cosx|-2are

Answer 1

Assuming θ is real, let us prove that mincosθ=−1 and maxcosθ=1.

First, let us notice that cos0=1 and cosπ=−1; therefore these values are indeed reached by the cos function.

But how can we prove that they are its extremum values? For that we need a relation on the function that is global, not restricted to specific values (otherwise, we cannot prove there doesn’t exist somewhere a θ for which cosθ is outside [−1,1]).please mark me as Brainlisest

Answer 2

Answer:

Step-by-step explanation:

cos x -2

-cos x-2

min value of cos x -2

-3

max value of cos x -2

-1

min value of -cos x -2

-3

max value of -cos x -2

-1

therefore min and max= -3 and -1