The minimum and maximum velocities of a projectile are 10m/s and 20m/s respectively.
The horizontal range and maximum height are respectively
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A projectile has always a constant velocity along the horizontal direction. At the time t=0, the projectile has the maximum speed vertically. At the maximum height the projectile has minimum (0) vertical speed.
Ф = angle of projection
So minimum speed = u CosФ = 10 m/s
Maximum speed = u = 20 m/s
So Cos Ф = 10/20 = 1/2 => Ф = 60°
Horizontal range = R = u² Sin2Ф / g = 20² Sin120° / 10
R = 20 √3 m
Maximum height = H = u² Sin²Ф /2g = 20² (3/4) /2*10
H = 15 m
Ф = angle of projection
So minimum speed = u CosФ = 10 m/s
Maximum speed = u = 20 m/s
So Cos Ф = 10/20 = 1/2 => Ф = 60°
Horizontal range = R = u² Sin2Ф / g = 20² Sin120° / 10
R = 20 √3 m
Maximum height = H = u² Sin²Ф /2g = 20² (3/4) /2*10
H = 15 m
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Answer: Hey dude answer is Range=20m and H maximum=15m
See the attachment for explanation
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