Question

The minimum and maximum velocities of an oblique projectile are 10 metre per second and 20 metre per second respectively the maximum height is

Answer 1

Answer:

Max height = 15 m

Explanation:

Maximum Velocity of oblique projectile is 20 m/s

Velocity is Max at throwing  or at back at ground

=> Initial Velocity = 20 m/s

Minimum Velocity = 10 m/s at Max height when Vertical Velocity becomes 0

=> Horizontal Velocity = 10 m/s

20 Cosα = 10

=> α = 60°

Angle of Projection = 60°

So vertical velocity at initial = 20Sin60  = 10√3

Using V² - U² = 2aS

V = 0 at max height U = 10√3

a = - g = -10

S = max height

=> 0² - (10√3)² = 2(-10)S

=> S = 300/20

=> S = 15

Max height = 15 m