Question

The minimum atomic number of an element in which number of s electron is equal the number of d elect

Answer 1

Answer:

22

Explanation:

1s2 2s2 2p6 3s2 3p6 4s2 *3d2*

In 3d2 it has 2 electrons which is same

Answer 2

The minimum atomic number of the element is 28.

• d orbital starts from the M shell.
• Hence before it, the K shell should contain 2 electrons in the 1s orbital and the L shell should contain 8 electrons in 2s and 2p orbital. Now the M shell should contain 8 electrons in 3s and 3p orbital.
• Now before filling the 3d orbital the 4s orbital should be filled up with 2 electrons.
• Thus the total number of s' electron is 2+2+2+2=8.
• Hence the number of d electrons is also 8.
• The electronic configuration is written as follows-
• ${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {4s}^{2} {3d}^{8}$
• Thus, the atomic number of the element is 28.