Question

The minimum concentration of Ag+ ions required in order to initiate the precipitation of AgCl from a solution containing 0.004 mol L–1 of Cl– ion will be [Ksp of AgCl = 1.8 × 10–10]​

Answer 1

Answer:

2.5 ×10−8 ⋅mol⋅L−1

Explanation:

The chemical reaction under equilibrium would be:

Ag+ + Cl−→AgCL(s)

As per question statement we are given that thermodynamic equilibrium constant for the  reaction, i.e.:

Ksp=[Ag+][Cl−]=1×10−10.

Ksp is also known as the solubility product. Now we are given the concentration of Cl- ions which is 0.004 or 4 x 10−3

Putting this in formula

[Ag+]=Ksp / [Cl-]= 1×10−10 / 4×10−3

=2.5 ×10−8 ⋅mol⋅L−1