Question

The minimum deviation angle occurred by a prism of peam
agle 60" is 30". Calculate the active index of the material​

Answer 1

Answer:

N=

$\sqrt{2}$

Explanation:

N=

$= > \sin((a + \alpha) \div 2 ) \div \sin(a \div 2)$

$= > \sin((60 + 30) \div2 ) \div \sin(60 \div 2)$

$= > \sin(45) \div \sin(30)$

$= > (1 \div \sqrt{2} ) \div (1 \div 2)$

$= > \sqrt{2}$

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