The minimum distance from real object to a image in a concava mirror is
Answers
Answered by
1
1/(-u) + 1/v = 1/(-f)
1/v = 1/u - 1/f, u, f are >0.
If u > f then v is negative. So real image is formed. So min is f.
If u is less than f then a virtual image is formed. u can be just about 0.
1/v = 1/u - 1/f, u, f are >0.
If u > f then v is negative. So real image is formed. So min is f.
If u is less than f then a virtual image is formed. u can be just about 0.
kvnmurty:
Click on the thanks button above
Similar questions