Physics, asked by sravan6, 1 year ago

the minimum distance from the real object to real image in concave mirror is?
2f, 0, 4f, f....
which is correct answer.. and explain it....

Answers

Answered by skyfall63
32

Answer:

The minimum distance is zero.

Explanation:

The concave mirror is the mirror which makes real image as well as the virtual image depending upon the position of the object placed in front of the mirror.

As we know that, when the object is placed at the "center of curvature", the "image" is formed is real. Beyond which, when the object is placed, the image formed by the concave mirror becomes virtual.

Thereby, considering the position from where the real image is formed and has least minimum distance, will be acquired when the object is placed at center of curvature represented by 2F.

Distance of object from mirror = u

Distance of image from mirror = v

And when object at 2F, image is formed at 2F

\mathrm{v}=\mathrm{u}

(\mathrm{v}-\mathrm{u})_{\text { minimum }}=0

The minimum "distance between the object" and real image is thus be zero.

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