Question

The minimum distance of a point (4, 2) from the parabola y2 = 8x is

Answer 1

let the point on parabola be
$( {h}^{2} \div 8 \: ...\: h) \\ \\ apply \: distance \: formula \\ d = \sqrt{( {h}^{2} \div 8 \: - 4) {}^{2} + (h - 2) {}^{2} }$
differentiate it and put =0...
find h