Chemistry, asked by roneys7809, 5 hours ago

The minimum energy required to overcome the attractive force between an electron and the surface of Ag metal is
5.22 x 10—19 J. What will be the maximum kinetic energy of electrons ejected out from Ag which is being exposed
to UV-light of lamda = 3600 Å?

Answers

Answered by anshuyadavysn

0

Answer:

e=hc/lambda

Explanation:

apply above formula and see the difference

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