The minimum force necessary to pull up a body along
a rough inclined surface is F. But it becomes F', when
applied parallel to the inclined plane. If y is the coeffi-
cient of friction between the body and the inclined
plane, show that F' = Fsqrt(1-mue square)
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Answer:
The minimum force required to start pushing a body up a rough inclined plane is
F
1
=mgsinθ+μgcosθ ......(i)
Minimum force needed to prevent the body from sliding down the inclined plane is
F
2
=mgsinθ−μgcosθ ...........(ii)
Divide (i) by (ii), we get
F
2
F
1
=
sinθ−μcosθ
(sinθ+μcosθ
=
tanθ−μ
tanθ+μ
=
2μ−μ
2μ+μ
=3 (tanθ=2μ (given))
Explanation:
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