Question

The minimum force required to move a body of mass 5 kg over a surface whose coefficient of fric
is 0.3 (g = 10 ms-2)
[
a) 15 N
b) 13 N
c) 12 N
d) 10 N​

Answer 1

Explanation:

Force applied must be greater than or equal to 15N.

Hope the workout attached above solves your doubt.

Answer 2

The minimum force required to move the body over the surface will be 15 N.

Given,

The mass of the body is 5 kg.

The coefficient of friction of the surface is 0.3.

To Find,

The minimum force required to move the body over the surface.

Solution,

The minimum force required to move the body over the surface will be equal to the frictional force.

Now, the formula of frictional force is

F = μN

where μ is the coefficient of friction and N is the normal reaction. { N = mg}

So,

F = (0.3)(5)(10)

F = 15 N

Hence, the minimum force required to move the body over the surface will be 15 N.

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