The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If co-efficient of friction between the body and inclined plane is 2/√3, the angle of inclined plane is
(A) 60° (B) 45° (C) 30° (D) 15°
deepasrisre:
please anyone....... answer this question☺
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I hope it's answer is 60°
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Answer:
Explanation: I can only give you a hint .ok.
u mg cos theeta + mg sin theeta = 3(mg sin theeta - u mg cos theeta)
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