Question

The minimum force required to move a body up an inclined plane of inclination 30 is found to be thrice the minimum force required to prevent it from sliding down the plane. Find the coefficient of friction between the body and the plane

Answer 1

HELLO DEAR,

minimum force required to move the body up on a inclined place is mgsin30 + umgcos30.

so, minimum force required to prevent from sliding is mgsin30 - umgcos30.

GIVEN:- thrice the minimum force required to prevent the sliding the plane the coefficient of friction VP

therefore,

mgsin30 + umgcos30 = 3(mgsin30 - umgcos30)

=> (mgsin30 - umgcos30)

=> 4umgcos30 = 2mgsin30

=> 2ucos30 = sin30

=> tan30 = 2u

=> u = 1/√3 × 1/2

=> u = 1/2√3

I HOPE IT'S HELP YOU DEAR,

THANKS

Answer 2

Help urself with the attachment