Question

the minimum horizontal speed with which a body should be projected so as to go round a smooth vertical circular track of radius 4m is​

Answer 1

Answer:

Explanation:

lets first find the maximum height of projectile

h=v^2/2g

now at the highest point the velocity in circular motion is root of (gr)

and at highest poni we have to take h=2r in circular motion

v^2/2g=2r

v^2=4gr=4*4*9.8=156.8

v=12.52

Answer 2

lets first find the maximum height of gunshot

h = v²/ 2g

now at the loftiest point the haste in indirect stir is root of( gr)

and at loftiest poni we've to take h = 2r in indirect stir

v²/ 2g = 2r

v² = 4gr = 4 × 4 × 9.8 = 156.8

v = 12.52

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