Question

The minimum magnifying power of telescope is m if the focal length of its eye lens is halved the magnifying power will be

Answer 1

Explanation :

It is given that,

The magnifying power of a telescope is m.

We know that the magnifying power of a telescope is given by :

$m=\dfrac{f_0}{f_e}$

where,

$f_0$ is the focal length of the lens or mirror of a telescope.

$f_e$  is the focal length of the eye piece.

In this case, the focal length of its eye lens is halved. Let the new magnification is m'.

So, $m'=\dfrac{f_0}{\dfrac{f_e}{2}}$

$m'=2\ m$

Hence, it is clear that if the focal length of the eyepiece is halved then the magnifying power becomes twice.

Answer 2

Answer:

can you please say where u got the particular question from?? any competitive exam question or from book?