Chemistry, asked by Lordvoldermort, 1 year ago

the minimum mass of mixture of a2 and b4 required to produce at least 1 kg of each product is given at. mass of a is 10 and at. mass of b is 120​

Answers

Answered by Anonymous
3

Answer:

here is your answer mate.......

explanation

It requires 8.9 mole A2 and 3.57 mole B4 respectively. Thus 10 mole A2 (200 g) and 4 mole B4 (1920 g) will produce atleast 1 kg of each product. The minimum mass of mixture required is 200g+1920g=2120g.

Answered by bittukumar963195
0

Answer:

Explanation:t requires 8.9 mole A2 and 3.57 mole B4 respectively. Thus 10 mole A2 (200 g) and 4 mole B4 (1920 g) will produce atleast 1 kg of each product. The minimum mass of mixture required is 200g+1920g=2120g

Similar questions