Question

The minimum number of terms of 1+ 3+5+7+.... that
add up to a number exceeding 1357 is​

Answer 1

Step-by-step explanation:

Sn=2n(2×1+(n−1)2)

=n2

Now, 362=1296 and 372=1369

∴{(n)min∣(n2>1357)}=37

Hence, option B is correct

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