Physics, asked by khandared95, 3 months ago

the minimum period of revolution of an artifical satellite in a circular orbit round the earth.

G=
6.67 \times 10 {}^{ - 11}
Nm2/kg2.
R=
 6.4 \times {10}^{ 6} m
M=
6 \times  {10}^{24} kg





Answers

Answered by binod31
1

Answer:

v(critical) = √GM/√(R+h)

after that t= 2πr/V(critical)

Similar questions