Question

the minimum phase difference between the two simple harmonic oscillations
​

Answer 1

Explanation:

ANSWER

y

1

=

2

1

sinωt+

2

3

cosωt

=A

1

sin(ωt+ϕ

1

)

y

2

=sinωt+cosωt

=A

2

sin(ωt+ϕ

2

) where ,

ϕ

1

=tan

−1

(

1/2

3

/2

=tan

−1

3

=

3

π

ϕ

2

=tan

−1

(1/1)=

4

π

Phase difference =ϕ=ϕ

1

−ϕ

2

=

3

π

−

4

π

=

12

π