Question

The minimum power of lense is 40d if the far point of normal eye is infinity find the size of eye

Answer 1

Answer:

As the image is formed on the retina, the size of the eyeball would be equal to the image distance (v). Now, as the object distance is infinite, we know that the image will be formed on the focus. So, here v = f (focal length). HELLO DEAR, P=1/F F=1/P =100/40 =2.5cm. R=2.5 MULTIPLY BY 2. R= 5cm then the size of eye ball is 5cm.

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Answer 2

The size of the eye is 5 cm.

Explanation:

Given that, the minimum power of lens is 40 D. Firstly, we will find the focal length of the lens. It is given by in terms of power as :

$f=\dfrac{1}{P}\\\\f=\dfrac{1}{40\ D}\\\\f=0.025\ m\\\\f=2.5\ cm$

The focal length of the eye is 2.5 cm. The radius of curvature of the lens gives the idea of the size of eye. So,

R = 2 f

$R=2\times 2.5\\\\R=5\ cm$

So, the size of the eye is 5 cm.

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