Question

The minimum refractive index of the prism given below
should be
Kincident ray
45°
emergent
ray
90°
45°​

Answer 1

Answer:

theta 1 (minimum)>critical angle(C)

theta 1=(angle of prism(A)-theta 2 )minimum; equation 1.

implies: theta 2 (maximum);

now by Snell's law theta 2(max) implies angle of incidence to be maximum;

angle of incidence i (maximum)= 90;

so, theta 2 (max)=critical angle(c);

so finally, A-C>C;(from equation 1)

A>2C