The minimum resistance possible by five equal five resistors by their combination is 2ohm.what will be the maximum resistance possible
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Minimum resistance means that they are connected in parallel
So let the resistance of all five resistors be x
1/x+1/x+1/x+1/x+1/x=1/2
5/x=1/2
x/5=2
x=10Ω
So now the maximum possible resistance will be when they are connected in series
So
R= 10+10+10+10+10
R=50Ω
So let the resistance of all five resistors be x
1/x+1/x+1/x+1/x+1/x=1/2
5/x=1/2
x/5=2
x=10Ω
So now the maximum possible resistance will be when they are connected in series
So
R= 10+10+10+10+10
R=50Ω
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