Question

The minimum rotational speed of the generator is 900 rpm in the operation rangeA-B. what is the value of omega min
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Answer 1

Given that,

Minimum rotational speed of the generator = 900 rpm

Angular velocity :

Angular velocity is equal to the linear velocity divided by the radius.

In mathematically,

$\omega=\dfrac{v}{r}$

Where, v = linear velocity

r = radius

We need to calculate the value of ω in rps

Using formula for angular speed

$\omega = 900\ rpm$

We know that,

$1\ rpm =\dfrac{2\pi}{60}\ rps$

So, $900\ rpm=900\times\dfrac{2\pi}{60}$

$900\ rpm=94.24\ rps$

Hence,  The value of ω is 94.24 rps.

Answer 2

Answer:

94.24

Explanation:

w=2πN/60

where N=900 rpm