Physics, asked by nani9259, 4 months ago

The minimum speed of projection required to strike the top of a pole of height 8m and located at a horizontal distance of 6m from the point of projection is nearly (g= 10m/s^(2))

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Answered by Itzvaibhav007

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A pole of height 4 m is kept in front of a vertical plane mirror of length 2 m. The lower end of the mirror is at a height of 6 m from the ground. ...

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The minimum speed of projection required to strike the top of a pole of height 8m and located at a horizontal distance of 6m from the point of projection is nearly (g= 10m/s^(2))​

Answers

The minimum speed of projection required to strike the top of a pole of height 8m and located at a horizontal distance of 6m from the point of projection is nearly (g= 10m/s^(2))