Math, asked by vijaychakali, 8 months ago

The minimum taxi fare is 20 for the first km and there after 8 for each
additional km.​

Answers

Answered by nikunjc971
2

Step-by-step explanation:

(i) Fare for first km = Rs. 15

Fare for second km = Rs. 15+8= Rs 23

Fare for third km = Rs. 23+8=31

Here, each subsequent term is obtained by adding a fixed number (8) to the previous term.

Hence, it is in A.P.

(ii) Let us assume, initial quantity of air =1 .....1)

Therefore, quantity removed in first step =

4

1

Remaining quantity after first step

1−

4

1

=

4

3

....2)

Quantity removed in second step

=

4

3

×

4

1

=

16

3

Remaining quantity after second step

=

4

3

16

3

=

16

9

....3)

Here, each subsequent term is not obtained by adding a fixed number to the previous term.

Hence, it is not an AP.

(iii) Cost of digging of 1

st

meter =150

Cost of digging of 2

nd

meter =150+50=200

Cost of digging of 3

rd

meter =200+50=250

Here, each subsequent term is obtained by adding a fixed number (50) to the previous term.

Hence, it is an AP.

(iv) Amount in the beginning = Rs. 10000

Interest at the end of 1

st

year @ 8% = 10000×8%=800

Thus, amount at the end of 1

st

year =10000+800=10800

Interest at the end of 2

nd

year @ 8% = 10800×8%=864

Thus, amount at the end of 2

nd

year =10800+864=11664

Since, each subsequent term is not obtained by adding a fixed number to the previous term; hence, it is not an AP.

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