the minimum temperature in tirupati on 10th December 2001 was 31°s. express it in Fahrenheit
Answers
Answered by
0
Answer:
87.8F
Step-by-step explanation:
0degree = 32 degree F
31degree = 87.8F
HOPE IT HELPS YOU
Answered by
0
Hey mate,
= ( C × 9/5 ) + 32
= ( 31 × 9/5 ) + 32
= ( 279/5 ) + 32
= 55.8 + 32
= 87.8° Fahrenheit .
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