the minimum value of (1 + cos 2x + 8 sin^2x)/(2 sin 2x) when x belongs to (0,pi/2)
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f(x) = 1 + cos2x+8sin^2xsin2x = cos^2 x + 4sin^2xsinxcosx = cot x + 4tan x cotx + 4tanx2>√(4) f(x)> 4 Minimum value of f(x) is 4 More
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