The minimum value of 4^x + 4^(1–x) , x ∈ R, is
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Since, x is an element of real number.
→ 4^x +4^1-x = 4^x +4/4^x = (4^2x+4)/ 4^x
→ 4^x +4^1-x = 4^x +4/4^x = (4^2x+4)/ 4^x
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