Question

The minimum value of f(x) = 16x^2 -16x +28 is..​

Answer 1

Answer:

$\mathfrak\red{yeh}$

Answer 2

Step-by-step explanation:

Given,

f(x)=16x

2

−16x+28

f(x)=16x

2

−16x+4+24

∴f(x)=(4x−2)

2

+24

we have, (4x−2)

2

≥0 for all x∈R

⇒(4x−2)

2

+24≥0+24 for all x∈R

∴f(x)≥24 for all x∈R

∴x=24 is the minimum value.

The function doesn't attain the maximum value at any point in its domain.