Question

The minimum value of f(x)=2x^2+3x+1 is

Answer 1

Answer:

$2 {x}^{2} + 3x + 1 = 0$

$= 2 {x}^{2} + (2 + 1)x + 1 = 0$

$= 2 {x}^{2} + 2x + x + 1 = 0$

$= 2x( x + 1) + (x + 1) = 0$

$= (2x + 1)(x + 1) = 0$

$= x = - 1 \: and \: x = \frac{ - 1}{2}$

i hope it will help u☺☺

Answer 2

Answer:

6 is the answer

Step-by-step explanation:

f(x) = 2x² + 3x + 1

x - 1 = 0

∴ x = 1

f(x) = 2(1)² + 3(1) + 1

= 2 + 3 + 1

= 6