Question

The minimum value of force acting between two point charges placed at 1m apart from one another is

Answer 1

Answer:

kq1q2

Explanation:

F=kq1q2/r²

r=1

so F=kq1q2

Answer 2

The minimum value of force acting between two point charges placed at 1m apart from one another is kq₁q₂.

• Consider the two charges apart from each other at 1m to each other and they both impart forces.
• So, the force due to another charge can be calculated by using the coulombic force law.
• According to the coulombic force law F=  kq₁q₂/r².
• The distance between the two charges is 1m So, so the force is kq₁q₂.
• The force can be attractive or repulsive depending on the nature of the charges.